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Mathematics, 09.10.2019 19:30 rerunkle96

The work of a student trying to solve the equation 2(2x βˆ’ 3) = 6 + 2x + 4 is shown below: step 1: 2(2x βˆ’ 3) = 6 + 2x + 4 step 2: 4x βˆ’ 3 = 10 + 2x step 3: 4x βˆ’ 2x = 10 + 3 step 4: 2x = 13 step 5: x = 6.5 in which step did the student first make an error and what is the correct step?

step 2: 4x βˆ’ 6 = 10 + 2x
step 2: 4x βˆ’ 3 = 2 + 2x
step 3: 4x + 2x = 10 + 3
step 3: 4x βˆ’ 2x = 10 - 3

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The work of a student trying to solve the equation 2(2x βˆ’ 3) = 6 + 2x + 4 is shown below: step 1:...
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