Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point (–6, 2).

y=+

y=1x+8

Step-by-step explanation:

Let's start with the general slope-intercept equation of a line, which is defined as:

(y-b)=m*(x-a), where:

(a,b) is a point belonging to the line, and, m is the line's slope.

The equation for the given line is:

y=x+11, which can be re-written as:

(y-11)=1(x-0)

This means that the slope of this line is m=1, and that a point belonging to the line is (0,11).

Since parallel lines are defined as lines with the same slope, then for the second line, we need to establish m=1.

Becuase the point (-6,2) is a point belonging to the second line, then we can express the general equation (y-b)=m*(x-a) as:

(y-2)=1(x-(-6)) which we can re-write as:

y=1(x-(-6))+2

y=1x+6+2

y=1x+8

In conclusion, the equation of a line that passes through the point (-6,2) and is parallel to the given line, can be described by the following equation in its slope-intercept form: y=1x+8.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

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