In triangle abc, a = 18.2, ∠b = 62°, and ∠c = 48°. find b 15

Measurement of side b = 17.1

Step-by-step explanation:

In a given triangle ABC, it is given a = 18.2, ∠B = 62° and ∠C = 48° and we have to find the measurement of b.

Now by Sine Rule

Here ∠C and ∠B are given so we can get the measurement of ∠A.

∠A + ∠B + ∠C = 180°

∠A + 62 + 48 = 180

∠A = 180 - 110 = 70°

Now we put these values in the sine rule.

Therefore measurement of side b will be 17.1

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.