Choose the equation of the vertical line passing through the point (8, −2). x = −2 y = −2 x = 8 y = 8

x = 8

Step-by-step explanation:

The general equation of a vertical line that passes through "a" is

.

Notice that x remains fixed at value "a" and y can take any value.

This can be understood by rewritting the above equation as

.

Then, the points ... (a, -2), (a, -1), (a, 0), (a, 1),(a, 2)... vertically aligned satisfy the above equations.

Now, returning to our specific exercise, we need the vertical line that passes through (8, -2). Since, the line is vertical, we have to focus on x-coordinate of the given point, and its value is 8.

Then, the equation of the vertical line passing through the point (8, −2) is

.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

answer: (-6,3)

step-by-step explanation: