Which construction can you use to prove the pythagorean theorem based on similarity of triangles?

Draw perpendicular to the hypotenuse that goes through point of right angle.

Step-by-step explanation:

Let ΔABC be any triangle right angled at B, then a line segment perpendicular to AC (hypotenuse) and name it point D such that in ΔABC and ΔABD, ∠B=∠ADB =90° and ∠A=∠A (common in both triangles) ,therefore by AA similarity criteria ΔABC is similar to ΔABD....> which can be use to prove the Pythagoras theorem.

Pythagoras  theorem states that in any right angled triangle the square of the longest side is equal to the sum of the square of other two sides.

Dbc if u do the math and stuff that what i got let me know if i was wrong

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for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

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