Find the side length labeled x, round intermediate values to the nearest tenth

90 is the answer 
you add 20 +90=110
than you 180-110=90

I am not sure if x is the portion of the line in the single triangle or if x is the whole line from the big triangle. So i will show you how to get both.

Well well if you notice the dotted line creates 2 right triangles. are given 2 angles so I can assume I will be using cosine or sine depending on whichtriangle we are woring with. The angle in the top of the left triangle is said to be 20 degrees. we know that
cos = adjacent/hypotenuse
tan = opp/adj
sin = opp/hyp

since the line is beside the 20 degree angle is opposite the 90 degree angle, it is the hypotenuse.

if x is only part of the smaller triangle on the right then we would need only to find the measure of the dotted line and we could use cosine because the dotted line is adjacent to the 20 degree angle and 33 is the hypotenuse. so:
cos (20) = x/33
33 * cos (20) = x

then we would have the side that is opposite the 30 degree angle in other triangle and x is adjacent so we use tan. so:
tan (30) = (33 * cos (20)) / x
x = (33 * cos (20)) / tan (30)

So so if x is only the smaller portion of line then:
x = 53.71 or rounded
x = 53.7

if it's the big line then we have to add in the smaller portion. The little part is opposite the 20 degrees so:
sin (20) = y / 33
33*sin (20) = y

y = 11.28 rounds to

y = 11.4

add this to other portion and get
x = 65.1

Ibelieve that c. recording would work best.