Asequence is defined recursively using the equation f(n + 1) = f(n) – 8. if f(1) = 100, what is f(6)? 52

Answer with Step-by-step explanation:

We are defined a sequence recursively as:

f(n + 1) = f(n) – 8

we are given f(1)=100

We have to find f(6)

f(2)=f(1)-8

f(3)=f(2)-8

    =f(1)-8-8

   = f(1)-16

f(4)=f(3)-8

    =f(1)-16-8

    =f(1)-24

f(5)=f(4)-8

    = f(1)-24-8

    =f(1)-32

f(6)=f(5)-8

    =f(1)-32-8

    =f(1)-40

    =100-40

   = 60

Hence, Value of f(6) given f(1)=100 is:

60

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