1. write the first four terms of the sequence whose general term is given.
an = 7n – 4

2. write a formula for the general term (the nth term) of each geometric sequence. then use the formula for an to find the eighth term of the sequence.
1, 2, 4, 8, …

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

this is not the answer this is just a question. is this middle school math?

step-by-step explanation: