What is the probability that 4 randomly selected people all have different birthdays? round to four decimal places?

There are 365 out of 365 ways to select the birthday of first person. Therefore the number of ways that we can choose a birthday for second person is 364 out of 365. Until the fourth person is 362 out of 365. We use the "mutually exclusive event of probability" and the answer is (365/365)*(364/365)*(363/365)*(362/365) = 0.9836

The first one is correct