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![\bf \sqrt[3]{-1000p^{12}q^3}\qquad \begin{cases} -1000= -10\cdot -10\cdot -10\\ \qquad\qquad (-10)^3\\ p^{12}=p^{4\cdot 3}\\ \qquad (p^4)^3 \end{cases}\implies \sqrt[3]{(-10)^3(p^4)^3q^3} \\\\\\ -10p^4q](/tpl/images/0357/7045/14242.png)
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What is the cube root of -1,000p12q3...
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