Triangle pqr has vertices p(–2, 6), q(–8, 4), and r(1, –2). it is translated according to the rule (x, y) → (x – 2, y – 16).

what is the y-value of p'?

the y-value of p' is
.

The y-value of P' is -10.

Step-by-step explanation:

We have been given the vertices of triangle PQR as: P(–2, 6), Q(–8, 4), and R(1, –2). We are asked to find the y-coordinate of point P' after a translation of (x, y) → (x – 2, y – 16).    

We can see that our given translation rule states that we need to translate x-coordinates of triangle PQR to 2 units to right and y-coordinates will be shifted downwards by 16 units.

We can see that y-coordinate of point P' is -10, therefore, the y-value of P' is -10.

c is the final : )

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.