Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0

A = 1
b = -6
c = (y^2 - 2y + 4)
x^2 - 6x + 9 - 9 + y^2 - 2y + 4
(x - 3)^2 - 9 + y^2 - 2y + 4
(x - 3)^2 - 5 + y^2 = 2y = 0
(x - 3)^2 + y^2 - 2y = 5
(x - 3)^2 - 2y = 5 - y^2
(x - 3)^2 = 5 - y^2 + 2y
(x - 3)^2 = 5 - y^2 + 2y
x - 3 = ¥√5 - y^2 + 2y
x = √5 -y^2 + 2y + 3, - √5 - y^2 + 2y + 3