Ajar contains only dimes and quarters. the number of quarters is 8 less than the number of dimes. the value of the coins is $4.30.
a) write an equation that you can use to solve for the number of dimes, d.
b) how many dimes are in the jar?
im clueless

Write out equations for each condition...

The number of quarters is 8 less than the number of dimes:

q=d-8

The value of the coins is $4.30.

Each quarter is worth 25 cents and each dime is worth 10 cents, and the total value of all of the coins is 4.3*100=430 cents so we can say:

25q+10d=430, and if we use q=d-8 from earlier in this equation we have:

25(d-8)+10d=430  perform indicated multiplication on left side

25d-200+10d=430  combine like terms on left side

35d-200=430  add 200 to both sides

35d=630 divide both sides by 35

d=18

So there are 18 dimes in the jar.