Rectangle abcd has coordinates a(−10, 5) , b(10, 5), c(10, 0) , and d(−10, 0) . rectangle a'b'c'd' has coordinates a ′ (−10,−5), b ′ (10,−5) , c'(10, 0) , and d ′ (−10, 0) . rectangle a"b"c"d" has coordinates a ′′ (−2, −1), b ′′ (2, −1) , c"(2, 0) , and d ′′ (−2, 0) . which transformations describe why rectangles abcd and a"b"c"d" are similar? rectangle abcd was reflected across the y-axis and then dilated by a scale factor of 5 to form rectangle a"b"c"d" rectangle abcd was reflected across the x-axis and then dilated by a scale factor of 1 5 to form rectangle a"b"c"d" . rectangle abcd was dilated by a scale factor of 1 5 and then rotated 90° counterclockwise to form rectangle a"b"c"d" rectangle abcd was dilated by a scale factor of 5 and then rotated 90° counterclockwise to form rectangle a"b"c"d" .

The correct transformation that is applied to Rectangle ABCD to get Rectangle A"B"C"D" is:

  Rectangle ABCD was reflected across the x-axis and then dilated by a scale factor of  1 5  to form Rectangle A"B"C"D" .

We are given vertices of rectangle ABCD as:

 A(−10, 5) , B(10, 5), C(10, 0) , and  D(−10, 0) .

Now we reflect the rectangle across the x-axis to get rectangle A'B'C'D' since the rule that is applied to this reflection is:

            (x,y)  → (x,-y)

Hence,

A(-10,5) → A'(-10,-5)

B(10,5) → B'(10,-5)

C(10,0) → C'(10,0)

D(-10,0) → D'(-10,0)

Now this rectangle A'B'C'D' is dilated by a scale factor of 1/5 to obtain rectangle A"B"C"D" ; Since the rule that is applied to this dilation is:

             (x,y) → (x/5,y/5)

Hence, we have:

A'(-10,-5) → A"(-2,-1)

B'(10,-5) → B"(2,-1)

C'(10,0) → C"(2,0)

D'(-10,0) → D"(-2,0)

answer: 43/157

this is the answer and if you try to prove me wrong your a meanie