In one day, a toy store sold 15 toy cars and 20 yo-yos for a total of $190. the next day, the toy store sold 3 toy cars and 12 yo-yos for a total of $102. what is the cost of one toy car?
$1 for one car
$2 for one car
$4 for one car
$8 for one car

Option B is the correct answer.

Step-by-step explanation:

Let the cost of toy car be p and yo yo be q.

We have in one day, a toy store sold 15 toy cars and 20 yo-yos for a total of $190

                15 p + 20 q = 190 eqn1

The next day, the toy store sold 3 toy cars and 12 yo-yos for a total of $102

                3 p + 12 q = 102 eqn2

eqn2 x 5 gives

                 15 p + 60 q = 510 eqn3

eqn3 - eqn1 gives

                 15 p + 60 q - (  15 p + 20 q ) = 510 - 190

                 40 q = 320

                       q = 8 $

Substituting in eqn1

                 15 p + 20 x 8 = 190

                    p = 2

Price of toy car = 2 $

Option B is the correct answer.

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!