Solve the system using the method of your choice: y = 2x – 2

x + 3y = 15

Y = 2x - 2

x + 3y = 15

I'll do substitution by solving for y:

y = 2x - 2

Solve for y for the second equation:

y = 5 - x/3

Substitute:

2x - 2 = 5 - x/3

Add x/3 to both sides:

7x/3 - 2 = 5

Add 2:

7x/3 = 7

Multiply by 3:

7x = 21

Divide by 7:

x = 3

Substitute x in for one of the original equations:

y = 2(3) - 2

y = 6 - 2

y = 4

The solution set is (3, 4).