The depreciating value of a semi-truck can be modeled by y = ao(0.85)x, where y is the remaining value of the semi, x is the time in years, and it depreciates at 15% per year. an exponential function comes down from the positive infinity and passes through the points zero comma seventy-five thousand. the graph is approaching the x-axis. what is the value of the truck initially, ao, and how would the graph change if the initial value was only $65,000?

Step-by-step explanation:

Given that the  depreciating value of a semi-truck can be modeled by

Since it crosses (0,75000) we find that when x =0 y = 75000

Substitute to get

So equation would be

If initial value is changed to 65000, the y intercept would be shifted down to

65000.  The whole curve would be a bit vertical down than the previous curve.

a is the correct

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: