In how many ways the number 13260 be written as product of 2 factors

Let nn be any positive integer, and let d(n)d(n) denote the number of positive divisors of nn. Positive divisors of nn appear in pairs {a,na}{a,na}. Pairs of divisors aa, nana are distinct except when n=a2n=a2. So if nn is not a perfect square, d(n)d(n) is even. If nn is a perfect square, then d(n)d(n) is odd. In other words,

Determining one of aa, nana fixes the other ‘‘‘‘complimentary”” divisor. Therefore the number of ways in which we can write n=a⋅b=a⋅nan=a⋅b=a⋅na is the number of ways in which we can choose aa.

If nn is not a perfect square, the number of such choices equals 12d(n)12d(n).

If nn is a perfect square, the number of such choices equals 12(d(n)−1)12(d(n)−1). We may combine the two cases by the expression

⌊d(n)2⌋⌊d(n)2⌋.

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

step- i d k and i d c : )

you: : 0

bye