In the parallelogram shown, ae = p − 8, ce = 2p − 58, and de = p + 15. what is the length of line segment eb?

a.42 units
b.50 units
c.65 units
d.73 units

This is the concept of geometry, to calculate for the length EB we proceed as follows;
Given that ABCD is a parallelogram, AE=EC and DE=EB
but
AE=p-8, CE=2p-58
thus;
p-8=2p-58
calculating for the value of p we get:
p-2p=-58+8
-p=-50
thus
p=50

hence the value of EB will be:
EB=DE
DE= p+15
substituting the value of p we get:
DE=50+15=65
thus;
DE=EB=65
The answer is EB=65

Ithink the correct answer is d.