Atriangular prism has a length of 5 inches, a base of 2 inches, a height of 2 inches, and sides of 2 inches and 3 inches. find the surface area of the prism.

Volume of the Triangular prism = 1/2 (base*height*length) 
V = 1/2 (2 * 2 * 5) 
V = 10 cubic inches. 

For the surface area, you can divide the prism into parts: 
It's made of three rectangles and two equal triangles. 

For the two triangles: 
The area of each of the triangles is 1/2(base x height) 
Area of each triangles = 1/2 (2 * 5) 
Area of each triangles = 5 inches^2. 

For the three rectangles: 
* one is equal to base x length, 
Rectangle1 = 2 x 5 
Rectangle1 = 10 inches^2. 

* another is equal to side 1 x length 
Rectangle2 = 3 x 5 
Rectangle2 = 15 inches^2 

* and the last is equal to side 2 x length. 
Rectangle3 = 3 x 5 
Rectangle3 = 15 inches^2 

Adding all the components up, 
10 + 15 + 15 + 5 + 5 = 50 inches^2 

Therefore, the surface area of the prism is greater than volume 50 > 10
 hpe this helps:)