According to the rational root theorem, the numbers below are some of the potential roots of f(x) = 10x3 + 29x2 – 66x + 27. select all that are actual roots. a) -9/2 b)-9/10 c) 3/5 d) 1 e) 3

answer : A , C , D

WE plug in each root in f(x)  and check whether we get value =0

When f(a) =0  then  'a' is the actual root

Lets start with -9/2, plug in -9/2 for x

Hence -9/2 is one of the actual root

now plug in -9/10 for x

Hence -9/10 is not an actual root

now plug in 3/5  for x

So 3/5 is one of the actual root

Now plug in 1 for x

So 1 is one of the actual root

Now plug in 3 for x

So 3 is not the actual root

Answer is -9/2  , 3/5  and 1

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation: