The spinner is equally likely to land on any of the five sections.

what is the probability that the spinner lands on an even number or on the unshaded section?

a- 1/5
b-2/5
c-3/5
d-4/5

we know that

the probability of an event is the ratio of the size of the event space to the size of the sample space.

the size of the sample space is the total number of possible outcomes

the event space is the number of outcomes in the event you are interested in.

so

p=size of the event space/size of the sample space

step

find the probability that the spinner lands on an even number

size of the sample size=

size of the event space=

step

find the probability that the spinner lands on the unshaded section

size of the sample size=

size of the event space=

step

find the probability that the spinner lands on an even number or on the unshaded section

sum the probability find in step and the probability find in step

therefore

the answer is

the probability is equal to

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

answer: x=3 and y=4

step-by-step explanation: