 such that 
![f(x)=15x-1\to y=15x-1\\\\15x-1=y\ \ \ \ |add\ 1\ to\ both\ sides\\\\15x=y+1\ \ \ \ \ |divide\ both\ sides\ by\ 15\\\\\boxed{x=\frac{y}{15}+\frac{1}{15}}\to\boxed{x=\frac{1}{15}y+\frac{1}{15}}\\\\\boxed{\boxed{[f(x)]^{-1}=\frac{1}{15}x+\frac{1}{15}}}](/tpl/images/0176/0437/50404.png)
Find the algebraic inverse.
f(x)=15x-1...
Answers: 1
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