Acube is numbered 1 through 6. if the cube is rolled twice, how many of the possible outcomes will have two even numbers

Possible outcome = 9

Step-by-step explanation:

Given : A cube is numbered 1 through 6. If the cube is rolled twice.

To find : How many of the possible outcomes will have two even numbers

Solution :  

When two dice rolled once the outcome will be,

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)  

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)  

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)  

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

Possible outcome will have two even numbers are : (2,2) (2,4) (2,6)  (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)

Possible outcome = 9

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: