For two consecutive integers, the sum of the smaller and twice the larger is 29. find the smaller integer.

Consecutive numbers are numbers that have a difference of 1

The smaller number is 9

Let the consecutive numbers be x and y, such that:

y = x + 1

From the question, we have:

x + 2y = 29

Substitute y = x + 1

x + 2(x + 1) = 29

Open brackets

x + 2x + 2 = 29

3x + 2 = 29

Subtract 2 from both sides

3x = 27

Divide both sides by 3

x = 9

Hence, the smaller number is 9

Read more about consecutive numbers at:

link

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb