Aprojectile is launched with an initial speed of 42 feet per second. it is projected at an angle of 50 degrees. how far does the projectile travel? how much farther does it travel if it is launched with an initial speed of 84 feet per second?

1) 53.95 ft ( approx )

2) 161.85 ft. ( approx )

Step-by-step explanation:

Given,

Initial velocity,

Also, the projected angle,

1) Thus, the distance travelled horizontally ( Range of the projectile motion ),

Where, g is the acceleration due to gravity that having the value 32.2 ft per second,

Hence, the projectile covers 53.95 feet ( approx )

2) If

Then the range would be,

Thus, the additional distance = 215.80 ft - 53.95 ft = 161.85 ft.

Hence, It will travel 161.85 ft extraa.

their is no graph showing

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: