Acoin is tossed twice. what is the probability of tossing heads and then tails, given that the coin already shows heads in the first toss?

a. 1/6
b. 1/4
c. 1/2
d. 1/3

Option C is the correct answer.

Step-by-step explanation:

We need to find the probability of tossing heads and then tails. We are given that first toss already shows heads. So now we need to find the probability of second toss showing tail.

Since the coin has only two faces probability of head or tail in one toss = 1/2.

So the probability of tossing heads and then tails = 1/2

Option C is the correct answer.

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b