If sin theta = sqrt(2/2), which could not be the value of theta?
-225 degrees
-45 degrees
-135 degrees
-405 degrees

The solution would be like this for this specific problem:

sin(θ°) = √(2)/2 

θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° − sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ 

360°*0 + 45° = 45° 
360°*0 + 135° = 135° 
360°*1 + 45° = 405° 

sin(225°) = -√(2)/2

225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta cannot be 225 degrees.

225° is not possible

Step-by-step explanation:

Given that

we have to choose the option which could not be the value of theta.

As sine is positive in second and fourth quadrant.

⇒

Also,

Therefore 225° is not possible

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.