Find the equation of a circle that has its center at (-4, 3) and has a radius of 5.

The resulting equation of the circle is x²+y²+8x-9y = 0

Step-by-step explanation:

The general form of equation of a circle is represented as:

(x-a)²+(y-b)² = r² with center (a,b) and radius r

Given the centre of (-4,3) and radius of 5

a = -4, b = 3, r = 5

Substituting this value into the general equation of a circle we have:

(x-(-4))²+(y-3)² = 5²

(x+4)²+(y-3)² = 5²

On expansion:

x²+8x+16+y²-9x+9 = 25

x²+y²+8x-9y+16+9-25 = 0

x²+y²+8x-9y = 0

how many players are there?

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).