How many pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix worth $1.50 per pound?

a. 9
b. 20
c. 114.5

9 pounds

Step-by-step explanation:

Let the amount of nuts be x

Cost of 1 pound nuts is $1.10

So, Cost of x pounds = $1.10 x

Cost of 1 pound of candy = $ 1.60

Cost of 36 pounds of candy =

So, total cost = 1.10 x + 57.6

Total weight = x+36

Cost of mixture per pound =

Now we are given that Cost of mixture per pound is $1.50

So,

Hence 9 pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix worth $1.50 per pound.

d is the answer

step-by-step explanation:

let soccer = x and golf = y

part a

1st equation: x + y = 125

2nd equation: x = y +45

part b

replace x in the 1st equation with the 2nd one:

y + 45 + y = 125

simplify:

2y + 45 = 125

subtract 45 from each side:

2y = 80

divide both sides by 2:

y = 80/2

y = 40

she plays golf for 40 minutes.

part c

no because she plays soccer for 45 minutes longer than golf 40 +45 =   85 minutes, not 80 minutes.