Figure abcd has vertices a(−2, 3), b(4, 3), c(4, −2), and d(−2, 0). what is the area of figure abcd?

The area of figure ABCD is:

                    24 square units.

We see that the given points form the vertices of a trapezium ABCD with bases AD and CB with measure,

AD= 3 units

and CB=5 units

and the height of the trapezium is: AB= 6 units.

Hence, the area of trapezium ABCD is:

         Hence, the area of figure ABCD is:

           24 square units.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!