Awaterfall has a height of 1400 feet. a pebble is thrown upward from the top of the falls with an initial velocity of 12 feet per second. the height, h, of the pebble after t seconds is given by the equation h equals negative 16 t squared plus 12 t plus 1400
h=−16t2+12t+1400. how long after the pebble is thrown will it hit the ground?

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.