What two consecutive while numbers does square root of 68 lie?

To find between what two consecutive whole numbers the square root of a number is, we find the perfect square of each number, until the result passes the desired number.Whole numbers: Countable, that is, 0, 1, 2,3,...The square of a number x is

Doing this, we get that the square root of 68 lies between 8 and 9.

Squares:

The square of 0 is The square of 1 is The square of 2 is The square of 3 is The square of 4 is The square of 5 is The square of 6 is The square of 7 is The square of 8 is The square of 9 is

68 is between, 64 and 81, thus, the square root of 68 is between the square root of 64 and the square root of 81, that is, the square root of 68 is between 8 and 9.

A similar example is given at link

You want to know the two numbers that squared are on either side of 68.

8^2 and 9^2=64 and 81

So the two consecutive numbers are 8 and 9