Given the arithmetic sequence where a1=6 and a5=-6 what is a3

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3