Jose is wrapping a stack of 100 coins in a paper holder. each coin is 1/8inch thick and has a diameter of 1 inch. how many square inches of paper will jose need to cover the stack of coins? use 3.14 for pi

The resulting figure of a stack of 100 coins will be a right circular cylinder. We assume that Jose wraps around the cylinder (so it means not including the bases). Therefore we are solving for the lateral surface area of the cylinder: LSA = 2πrh.

To solve for height h, we multiply the thickness of the coin 100 times.
h = 100 * 1/8 in = 12.5 inches
Solving for radius r:
r = 1 inch/2 = 0.5 inches

LSA = 2(3.14)(0.5 in)(12.5 in) = 39.25 square inches 

Jose will need 39.25 square inches of paper to wrap the stack of coins.