Aquantity a varies inversely as a quantity b, if, when b changes, a changes in the inverse ratio. what happens to the quantity a if the quantity b doubles?

if the quantity b doubles, then a becomes half

Step-by-step explanation:

A quantity a varies inversely as a quantity b.

⇒

⇒ where, k is constant

When b changes, a changes in the inverse ratio i.e,

We have to find what happens to the quantity a if the quantity b doubles.

If the quantity b doubles.

then;

⇒the quantity a become half

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560