During a dig, an archaeological team starts at an elevation of −512 feet. at a rate of 234 feet per hour, the team digs deeper into the surface for 312 hours. for the next 412 hours, the team digs at a rate of 1512 feet per hour. then the team quits for the day.

The rate of their dig is 2 3/4 ft per hr for 3 1/2 hours, then the total distance dug after 3 1/2 hours should be: 9 5/8 ft

Here’s how we get the total distance:

 First, change mixed number into improper fraction and proceed to multiplication

2 3/4--> 11/4  and  3 1/2  becomes 7/2

Multiply.

11/4  x  7/2  = 77/8

Simplify 77/8--> 9 5/8 ft

Let us move on at the rate of 1 5/12 ft per hr for the next 4 1/2 hr,

Following the same procedure as above, the distance would be: 6 9/24 ft

Distance= 1 5/12 x 4 1/2

       = 17/12 x 9/2

       = 153/24

       = 6 9/24 ft

Thus,to sum up everything, they have a total dug of:

 9 5/8 + 6 9/24 = 9 15/24 + 6 9/24 = 16 ft

Then, their elevation on that day is -5 1/2 - 16 = -21 1/2 ft

mk./km: lm

step-by-step explanation:

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; mk

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