Arectangular dartboard has an area of 648 square centimeters. the triangular part of the dartboard has an area of 162 square centimeters. a dart is randomly thrown at the dartboard.
assuming the dart lands in the rectangle, what is the probability that it lands inside the triangle?

to the nearest whole percent, the probability is

   we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

the probability is equal to

P=size of the event space/size of the sample space

In this problem

size of the sample size=area of the rectangular dartboard=

size of the event space=area of the triangular part=

Convert to percentage

therefore

the answer is

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

idk

step-by-step explanation: