What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?

x = –1 – and x = –1 +
x = –1 – and x = –1 +
x = –1 – and x = –1 +
x = –1 – and x = –1 +

we have

To find the zeros equate the function to zero

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

Complete the square. Remember to balance the equation by adding the same constants to each side

Rewrite as perfect squares

square root both sides

therefore

the answer is

The zeros of the quadratic function are

and

, .

Step-by-step explanation:

The given quadratic equation function is f(x) = 6x²+12x -7

To find the zeros of the quadratic equation we rewrite the function as

6x² + 12x - 7 = 0

Now we know the quadratic formula to get the solutions as

here a = 6

b = 12

c = -7

By putting these values in the formula

and

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons