![\bf 4^{-x}=\sqrt[8]{\cfrac{1}{32}}\qquad \begin{cases} 4=2^2\\ 32=2^5 \end{cases}\implies (2^2)^{-x}=\sqrt[8]{\cfrac{1}{2^5}} \\\\\\ 2^{-2x}=\sqrt[8]{2^{-5}}\implies 2^{-2x}=2^{\frac{-5}{8}}\impliedby \begin{array}{llll} \textit{same base, thus the}\\ \textit{exponents must the same} \end{array} \\\\\\ -2x=-\cfrac{5}{8}\implies \boxed{x=\cfrac{5}{16}}](/tpl/images/0477/9337/12d6e.png)
Precalculus
given the exponential equation: ,(see image) find a common base and solve fo...
Mathematics, 28.01.2020 18:45 jamessmith86
Precalculus
given the exponential equation: ,(see image) find a common base and solve for x.
images of 4 answers and image of the problem are included.
Answers: 3
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