Carbon-14 has a half-life of approximately 5,730 years. this exponential decay can be modeled with the function n(t) = n0. if an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years? round the answer to the nearest hundredth.

After the period of 14,325 years, the amount of Carbon-14 remained is 35.356 atoms.

The half-life of the substance can be defined a the time required for the substance to reduce to half of the concentration.

The half-life can be calculated as:

 ........ (i)

where is the quantity of substance remaining

is the initial quantity

t is the time of decay

is the half-life of the substance.

In the question, = 200, t = 14,325 years, and = 5730 years.

Substituting the values in equation (i),

= 35.356 atoms.

After the period of 14,325 years, the amount of Carbon-14 remained is 35.356 atoms.

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34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

the one below it is a function