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what are the ratios for sin a and cos a? the diagram is not drawn to scale
a. sin a = 5/13, cos a = 12/13
b. sin a = 12/13, cos a = 5/13
c. sin a = 12/13, cos a = 5/12
d. sin a = 12/5, cos a - 5/14
you!

B. sin A = 12/13, cos A = 5/13

Step-by-step explanation:

The given triangle is a right triangle. In the right triangle, the hypotenuse = 13, Opposite side = 12 and Adjacent side = 5 with respect to the ∠A.

sin and cos are the trigonometric ratios.

sin = opposite / hypotenuse

cos = Adjacent /hypotenuse

With respect to ∠A.

sin A = Opposite /Hypotenuse.

Now plug in opposite side = 12 and hypotenuse = 13 to get sin A

sin A = 12/13

cos A = Adjacent/Hypotenuse.

Here adjacent side =5 and hypotenuse = 13.

So, cos A = 5/13

Therefore answer is B. sin A = 12/13, cos A = 5/13

answer: 1 and 3

step-by-step explanation: