What is the general form of the equation for the given circle centered at o(0, 0)?
a. x^2 + y^2 + 41 = 0
b. x^2 + y^2 − 41 = 0
c. x^2 + y^2 + x + y − 41 = 0
d. x^2 + y^2 + x − y − 41 = 0

Option B. x² + y²- 41 = 0

Step-by-step explanation:

We have to find the equation of a circle with center as (0, 0) and a point on circle is (4, 5).

Since standard equation of a circle is x² + y² = r² with origin(0, 0) as center.

radius r = √(4-0)²+(5-0)² = √(16+25) = √41

Therefore equation of the circle will be

x² + y² = 41

x² + y²- 41 = 0

Option B. is the correct option.

in mathematics, a function is a relationship between two variables such that the value of one of the variables, called the dependent variable, is determined by the value of the other variable, called the independent variable. there is a specific term we use to describe the set of independent variables of a function.