For which set of probabilities would events a and b be independent?

a) p(a) = 0.20; p(b) = 0.20; p(a and b) = 0.4
b) p(a) = 0.08; p(b) = 0.40; p(a and b) = 0.20
c) p(a) = 0.16; p(b) = 0.24; p(a and b) = 0.08
d) p(a) = 0.30; p(b) = 0.20; p(a and b) = 0.06

P(A) = 0.30; P(B) = 0.20; P(A and B) = 0.06

Two events (A and B) are independent if the probability of the intersection is the

same as the product of each individual probability: P(A and B) = P(A) · P(B).

Step-by-step explanation:

That's sad that the brainliest went to someone that didn't even answer.

so, converting firstly the mixed fractions to improper fractions and then "adding".

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.