Triangle qst is isosceles, and bisects t.

what is true about qrt? check all that apply.

qrt = 90°
qrt = srt
qrt stq
qrt = 2*rtq
qrt rtq

The correct options are 1 and 2.

Step-by-step explanation:

Given information: Triangle QST is isosceles, and bisects T.

In triangle QRT and SRT,

                               (common side)

                       (Bisector)

                       (Isosceles triangle)

By SAS rule,

                       (CPCTC)

Bisector of an isosceles triangle is the altitude of triangle.

Therefore options 1 and 2 are correct.

u dumb boi

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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