Peed of plane a = 415 mph. speed of plane b = 375 mph. both planes leave from new york city at the same time. plane a flies due north. plane b flies due south. after 4 hours, how far is plane a from plane b (to the nearest mile)?

Hence, distance between Plane A and Plane B is:

3160 m.

Step-by-step explanation:

It is given that:

Speed of Plane A = 415 mph.

Speed of Plane B = 375 mph.

Now  Both planes leave from New York City at the same time. Plane A flies due North and  Plane B flies due South.

This means that Plane A and Plane B travels in the opposite directions.

So the distance between them keep on increasing with respect to time.

We know that:

Distance=Speed×Time.

The distance covered by Plane A in 4 hours=415×4=1660 m.

The distance covered by Plane B in 4 hours=375×4=1500 m.

Hence, distance between plane A and Plane B in 4 hours=1660+1500

        =3160 m.