Aball is thrown into the air with an upward velocity of 32 ft/s. its height h in feet after t seconds is given by the function h = –16t2 + 32t + 6. a. in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. b. what is the ball’s maximum height?
a. 1 s; 22 ft

b. 2 s; 22 ft

c. 1 s; 54 ft

d. 2 s; 6 ft

A. 1 second ; 22 ft

Step-by-step explanation:

We have been given that a ball is thrown into the air with an upward velocity of 32 ft/s. Its height h in feet after t seconds is given by the function .

a. To find the time it will take the ball to reach its maximum height, we need to find x-coordinate of vertex of our given parabola.

We will use to find the x-coordinate of vertex of our given parabola.

Therefore, the ball will reach its maximum after 1 second.

b. To find the ball's maximum height we need to evaluate our given equation at .

Therefore, the maximum height of ball is 22 ft.

Upon looking at our given choices we can see that option A is the correct choice.

(x+3)(x+7)

step-by-step explanation:

step-by-step explanation: