The complete set of common factors of 6 and 12 is:
a.{6, 12}
b. {1, 6, 12}
c. {1, 2, 3}
d. {1, 2, 3, 6}
e. {24, 48}

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.