What are the zero(s) of the function f(x) = the quantity of 4 x squared minus 36 x, all over x minus 9?

x=0 is the root for the given function

Explanation:

We have been given with the function

 taking out  4x as the common factor from numerator then we will get

Now cancel out the common factor from numerator and denominator we will get

4x=0

Hence, x=0 is the zero of the given function

Zero of the function is solution of the function the point where function gives the value zero

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

5x+2x=49

7x=49

x=7. 35 apples