What are the minimum first quartile median third quartile and maximum of the data set
12 6 9 3 10 15 18 7

what are the minimum first quartile median third quartile and maximum of the data set
50 60 130 200 180 150 100 140

The smallest value in your data is your minimum. The greatest value is your maximum. In order to calculate the other three terms you asked for, you need to put your data in numerical order, and find the median. The median is the middle value. After putting your data in numerical order (smallest to greatest) (you have an odd number of values in your data), your eighth number is your median. 
1, 4, 4, 4, 5, 5, 6, 6, 6, 6, 7, 7, 8, 8, 10
If you place, parenthesis around the first set of data before your median, this set, will be used to find your first quartile. If you place parenthesis around the last set of data after your median, this set will be used to find your third quartile.
(1, 4, 4, 4 , 5, 5, 6), 6, (6, 6, 7, 7 , 8, 8, 10)
The median of the lower set of data, is the value of the first quartile, also known as Q1. Here it is a 4.
The median of the upper set of data, is the value of the third quartile, also known as Q3. Here it is a 7.
So your five number summary is as follows:
Min = 1, Q1 = 4, Med = 6, Q3 = 7, Max = 10

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°